daisy38
Answered

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determine the distance between P and Q.9.P(3,5) Q(3,-2)​

Sagot :

DISTANCE

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[tex]\large\sf\underline{Problem:} [/tex]

  • determine the distance between P and Q.
  • P(3,5) Q(3,-2)

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[tex]\large\sf\underline{Answer:}[/tex]

[tex] \qquad \huge \rm PQ = 7\:units[/tex]

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[tex]\large\sf\underline{Solution:}[/tex]

Determine the length from point P to point Q using the given formula.

[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\bold{formula : } \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \\ \boxed{\rm D= \sqrt{(x_2 - x_1 {)}^{2} + (y_2 - y_1 {)}^{2} } }\end{gathered} \end{gathered}\end{gathered} \end{gathered} [/tex]

  • [tex]\tt{(x_1, y_1) = (3,5) }[/tex]
  • [tex]\tt{(x_2, y_2) = (3,-2) }[/tex]

Substitute in the two values of x and y coordinates.

  • [tex]\rm PQ = \sqrt{(3 \:- \:3{)}^{2} + (-2\:-\:5{)}^{2} }[/tex]

  • [tex]\rm PQ = \sqrt{(0 {)}^{2} + (-7{)}^{2} }[/tex]

  • [tex]\rm PQ = \sqrt{(0) + (49)}[/tex]

  • [tex]\rm PQ = \sqrt{49}[/tex]

  • [tex]\rm PQ = 7 [/tex]

Therefore, the distance between point P to point Q is 7 units

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