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What is the molal concentration of 30 % ethanol solution (c2h5oh)?

Sagot :

yshamae2011

Answer:

The molality of the solution is 8.919 molal.

Explanation:

Molality (m) is defined as moles of solute per kilogram of solvent. On the other hand, molarity (M) is a unit of concentration which has a unit of moles of solute per liters of solution.

Let us keep these in mind as we go further to the solution for this problem.

Given:

5.86 M (molar) of ethanol (C₂H₅OH)

Required:

Molality (m)

Solution:

We assume 1 liters of solution for this problem.

Get first the molar mass (MM) of the ethanol.

MM ethanol = (12.012 g/mol*2) + (1.008*5) + (15.999) + (1.008)

MM ethanol = 46.071 g/mol

Getting the mass of ethanol from 5.86 M, we have,

5.86 moles ethanol (since we assume 1 L of solution)

5.86 moles ethanol * 46.071 g/mol = 269.9761 grams ethanol

Getting the mass of solution from the density, we have,

0.927 g/mL * 1000 mL = 927 grams solution

(We used multiplier 1000 mL because 1 L = 1000 mL)

Solving for the mass of solvent, we have,

mass of solvent = mass of solution - mass of solute

mass of solvent = 927 grams - 269.9761 grams

mass of solvent = 657.024 grams solvent = 0.657024 kilograms solvent

Solving for molality, we have,

m = moles solute ÷ kilograms of solvent

m = 5.86 moles of ethanol ÷ 0.657024 kg solvent

m = 8.919

Therefore, the molality of the solution is 8.919 molal.

aiahfaithdenosta

Answer:

7.34 m

Explanation:

Answer can be found in this link: https://www.assignmentexpert.com/homework-answers/chemistry/organic-chemistry/question-137007

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