Maryjanelucion0106
Answered

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a bag has 1 blue 3 green 2 red and 2 yellow marble . find the probability of drawing :

5.blue marble? a.1/8 b.1/4 c.1/7 d.1

6.green marble? a.1/8 b.4/3 c.1/5 d.3

7. yellow marble? a.1/8 b.3/8 c.1/4 d.2

8.white marble? a.1/8 b.3/4 c.1/5 d.0​

Sagot :

Gusion8484

[tex]\Large\sf\color {red}{✨Question:✨}[/tex]

A bag has 1 blue, 3 green, 2 red, and 2 yellow marble. Find the probability of drawing:

[tex]\Large\sf\color {red}{✨Answer:✨}[/tex]

[tex]➶➶➶➶➶➷➷➷➷➷➶➶➶➶➶ ➷➷➷➷➷[/tex]

5. A. [tex]\frac{1}{8}[/tex]

6. D. [tex]\frac{3}{8}[/tex]

7. C. [tex]\frac{1}{4}[/tex]

8. D. 0

[tex]➶➶➶➶➶➷➷➷➷➷➶➶➶➶➶ ➷➷➷➷➷[/tex]

[tex]\Large\sf\color {red}{✨Explanation:✨}[/tex]

Hope it helps

[tex]\Large\sf\color {red}{✨CarryOnLearning✨}[/tex]

[tex]\small\sf\color {skyblue}{-Gusion8484}[/tex]

rktmobilez

Question:

a bag has 1 blue 3 green 2 red and 2 yellow marble . find the probability of drawing :

5.blue marble? a.1/8 b.1/4 c.1/7 d.1

6.green marble? a.1/8 b.4/3 c.1/5 d.3

7. yellow marble? a.1/8 b.3/8 c.1/4 d.2

8.white marble? a.1/8 b.3/4 c.1/5 d.0​

Answer:

solve for Probability of desired event P(event) as,

[tex]\sf P(event) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P = Probability of Desired Event}\\\\\text{\sf FO = Favored Outcome = depends on desired event}\\\\\text{\sf TO = Total Outcome = Total number of objects}[/tex]

#5.  Solve for Probability of drawing a blue marble P(blue),

[tex]\sf P(blue) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P(blue) = Probability of drawing a blue marble}\\\\\text{\sf FO = Favored Outcome = 1 (1 blue marble)}\\\\\text{\sf TO = Total Outcome = 8 (8 total marbles)}\\\\\sf P(blue) = \frac{FO}{TO} \\\\\sf P(blue) = \frac{1}{8}\\\\\\[/tex]

#6.  Solve for Probability of drawing a green marble P(green),

[tex]\sf P(green) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P(green) = Probability of drawing a green marble}\\\\\text{\sf FO = Favored Outcome = 3 (3 green marbles)}\\\\\text{\sf TO = Total Outcome = 8 (8 total marbles)}\\\\\sf P(green) = \frac{FO}{TO} \\\\\sf P(green) = \frac{3}{8}\\\\\\[/tex]

#7.  Solve for Probability of drawing a yellow marble P(yellow),

[tex]\sf P(yellow) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P(yellow) = Probability of drawing a yellow marble}\\\\\text{\sf FO = Favored Outcome = 2 (2 yellow marbles)}\\\\\text{\sf TO = Total Outcome = 8 (8 total marbles)}\\\\\sf P(yellow) = \frac{FO}{TO} \\\\\sf P(yellow) = \frac{2}{8}\\\\\sf P(yellow) = \frac{1}{2} \\\\\\[/tex]

#8.  Solve for Probability of drawing a white marble P(white),

[tex]\sf P(white) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P(white) = Probability of drawing a white marble}\\\\\text{\sf FO = Favored Outcome = 0 (0 white marble)}\\\\\text{\sf TO = Total Outcome = 8 (8 total marbles)}\\\\\sf P(white) = \frac{FO}{TO} \\\\\sf P(white) = \frac{0}{8} \\\\\sf P(white) = 0\\\\\\[/tex]

* as always, double check my answers for errors or carelessness.

#Answers with no solution are as good as copy paste solution!

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