Learning Task 2: Find the sum and difference.
- 1.) [tex] \frac{8}{8} - \frac{5}{8} = \frac{3}{8} [/tex]
- 2.)[tex] \frac{6}{12} + \frac{4}{6} = \frac{6}{12} + \frac{4 \times 2}{6 \times 2} = \\ \frac{6}{12} + \frac{8}{12} = \frac{14}{12} \div \frac{2}{2} = \frac{7}{6} or1 \frac{1}{6} [/tex]
- 3.)[tex] \frac{8}{15} + \frac{3}{15} = \frac{11}{15} [/tex]
- 4.) [tex] \frac{10}{18} - \frac{3}{9} = \frac{10}{18} - \frac{3 \times 2}{9 \times 2} = \\ \frac{10}{18} - \frac{6}{18} = \frac{4}{18} \div \frac{2}{2} = \frac{2}{9} [/tex]
- 5.)[tex] \frac{4}{20} + \frac{7}{15} = \frac{4 \times 15}{20 \times 15} + \frac{7 \times 20}{15 \times 20} = \\ \frac{60}{300} + \frac{140}{300} = \frac{200}{300} \div \frac{100}{100} = \frac{2}{3} [/tex]
- 6.)[tex] \frac{4}{5} - \frac{15}{25} = \frac{4 \times 5}{5 \times 5} - \frac{15}{25 } = \\ \frac{20}{25} - \frac{15}{25} = \frac{5}{25} \div \frac{5}{5} = \frac{1}{5} [/tex]
- 7.)[tex]5 \frac{3}{4} - 3 \frac{5}{6} = \frac{23}{4} - \frac{23}{6} = \frac{23 \times 6}{4 \times 6} - \frac{23 \times 4}{6 \times 4} = \\ \frac{138}{24} - \frac{92}{24} = \frac{46}{24} \div \frac{2}{2} = \frac{23}{12} or1 \frac{11}{12} [/tex]
- 8.)[tex]3 \frac{2}{3} - 5 \frac{5}{9} = \frac{11}{3} - \frac{50}{9} = \frac{11 \times 3}{3 \times 3} - \frac{50}{9} = \\ \frac{33}{9} - \frac{50}{9} = \frac{17}{9} or 1\frac{8}{9} [/tex]
- 9.) [tex]7 \frac{3}{10} + 9 \frac{12}{15} = \frac{73}{10} + \frac{147}{15} = \\ \frac{73 \times 15}{10 \times 15} + \frac{147 \times 10}{15 \times 10} = \\ \frac{1095}{150} + \frac{1470}{150} = \frac{2565}{150} \div \frac{15}{15} = \\ \frac{171}{10} or17 \frac{1}{171} [/tex]
Learning Task 3: Find the sum and difference.
- 1.) [tex] \frac{10}{12} - \frac{2}{3} = \frac{10}{12} - \frac{2 \times 4}{3 \times 4} = \\ \frac{10}{12} - \frac{8}{12} = \frac{2}{12} \div \frac{2}{2} = \\ \frac{1}{6} [/tex]
- 2.)[tex] \frac{11}{12} - \frac{1}{3} = \frac{11}{12} - \frac{1 \times 4}{3 \times 4} = \\ \frac{11}{12} - \frac{4}{12} = \frac{7}{12} [/tex]
- 3.)[tex] \frac{1}{2} - \frac{2}{5} = \frac{1 \times 5}{2 \times 5} - \frac{2 \times 2}{5 \times 2} = \\ \frac{5}{10} - \frac{4}{10} = \frac{1}{10} [/tex]
- 4.)[tex] \frac{1}{6} + \frac{3}{5} = \frac{1 \times 5}{6 \times 5} + \frac{3 \times 6}{5 \times 6} = \\ \frac{5}{30} - \frac{18}{30} = \frac{13}{30} [/tex]
- 5.)[tex] \frac{5}{8} + \frac{1}{2} = \frac{5 \times 2}{8 \times 2} + \frac{1 \times 8}{2 \times 8} = \\ \frac{10}{16} + \frac{8}{16} = \frac{2}{16} \div \frac{2}{2} = \frac{1}{8} [/tex]
- 6.)[tex] \frac{3}{16} + \frac{3}{4} = \frac{3 \times 4}{16 \times 4} + \frac{3 \times 16}{16 \times 4} = \\ \frac{12}{64} + \frac{48}{64} = \frac{36}{64} \div \frac{4}{4} = \frac{9}{16} [/tex]
- 7.)[tex] \frac{2}{4} - \frac{9}{20} = \frac{2 \times 20}{4 \times 20} - \frac{9 \times 4}{20 \times 4} = \\ \frac{40}{80} - \frac{36}{80} = \frac{4}{80} \div \frac{4}{4} = \frac{1}{20} [/tex]
- 8.)[tex] \frac{12}{28} + \frac{11}{35} = \frac{12 \times 35}{28 \times 35} + \frac{11 \times 28}{35 \times 28} = \\ \frac{420}{980} + \frac{308}{980} = \frac{112}{980} \div \frac{28}{28} = \frac{4}{35} [/tex]
Answers:
Learning Task 2
- 1.) [tex] \frac{3}{8}[/tex]
- 2.) [tex] 1\frac{1}{6}[/tex]
- 3.) [tex] \frac{11}{15}[/tex]
- 4.) [tex] \frac{2}{9}[/tex]
- 5.) [tex] \frac{2}{3}[/tex]
- 6.) [tex] \frac{1}{5}[/tex]
- 7.) [tex] 1\frac{11}{12}[/tex]
- 8.) [tex] 1\frac{8}{9}[/tex]
- 9.) [tex] 17\frac{1}{171}[/tex]
Learning Task 3
- 1.) [tex] \frac{1}{6}[/tex]
- 2. [tex] \frac{7}{12}[/tex]
- 3. [tex] \frac{1}{10}[/tex]
- 4.) [tex] \frac{13}{30}[/tex]
- 5.) [tex] \frac{1}{8}[/tex]
- 6.) [tex] \frac{9}{16}[/tex]
- 7.) [tex] \frac{11}{20}[/tex]
- 8.) [tex] \frac{4}{35}[/tex]
- NOTE: To change mixed number into improper fraction you need times the denominator by the whole number and add the numerator and the answer will be the numerator by the same denominator.
- NOTE: To change improper fraction to mixed number you will divide the numerator by the denominator the answer will be the whole number and the remainder will be the numerator by the same denominator.
Learn with Brainlyシ︎
