ANSWER
1.) Evaluate 3x + 5 when x = 2
We replace x by 2, we have
Perform the indicated operation by;
- [tex]\large3(2) + 5 \: \: {\longrightarrow} \: \: {\small{\green{\rm{multiplication \: first}}}}[/tex]
- [tex]\large6 + 5 \: {\longrightarrow} \: {\small{\blue{\rm{addition \: second}}}}[/tex]
So when x = 2, 3x + 5 is equal to 11
Answer: [tex]\large{\boxed{11}}[/tex]
2.) Evaluate 6x - 2y when x =3 and y = 2
We replace x by 3 and y by 2
- [tex]6(3) - 2(2)[/tex]
- [tex]18 - 4[/tex]
- [tex] = 14[/tex]
Therefore when x = 3 and y = 2, 6x - 2y is equal to 14
Answer: [tex]\large{\boxed{14}}[/tex]
3.) Evaluate 3x² + 2x - 5 when x = 2
SOLUTION;
- [tex] \tt \: {3x}^{2} + 2x - 5[/tex]
- [tex]\tt \: = 3(2 {)}^{2} + 2(2) - 5[/tex]
- [tex] = 3(4) + 2(2) - 5[/tex]
- [tex] = 12 + 4 - 5[/tex]
- [tex] = 11[/tex]
Substitute x as 2
Evaluate the power first, then, multiply
Add and subtract
Answer: [tex]\large{\boxed{11}}[/tex]]
#CarryOnLearning^^