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if y varies inversely as the square of x . if y =8 when x=2,find the value of y when x =4​

Sagot :

[tex]\Large\color{aqua}\underline\mathbb{INVERSE \: VARIATION}[/tex]

if y varies inversely as the square of x . if y =8 when x=2,find the value of y when x =4​.

[tex]\\[/tex]

y varies inversely as the square of x

  • y = k/x²

To determine the missing value, we should determine first the constant. And to determine the constant, substitute the given first values of x and y to the equation of variation.

[tex]\\[/tex]

Given values:

  • y = 8, x = 2
  • y = k/x²
  • 8 = k/(2)²
  • 8 = k/4
  • (8)(4) = k
  • 32 = k

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The constant of variation is given. Now substitute the second given values of x and y to the equation of variation.

  • y = ?, x = 4
  • y = 32/x²
  • y = 32/(4)²
  • y = 32/16
  • y = 2

[tex]\\[/tex]

[tex]\color{blue}\underline\mathbb{ANSWER:}[/tex]

  • ∴ Therefore, the value of y is 2.

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[tex]\tt\color{aqua}{8:55 \: am}[/tex]

[tex]\tt{3/4/22}[/tex]