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Sagot :
Slope-intercept form is denoted as y = mx + b where, m is the slope and b is the y-intercept.
We will first find the slope by using m = (y2 - y1) / (x2 - x1) where (x1,y1) &
(x2, y2) are the two given points which are (2,1) & (3,-2).
Let's solve now
m = (y2 - y1) / (x2 - x1)
m = (-2 - 1) / (3 - 2)
m = -3 / 1
m = -3
Now, our slope is m = -3
Next, we will find the y-intercept (b) by using the slope m=-3 and one of the two points like (2,1)
y = mx + b
1 = -3(2) + b
1 = -6 + b
1 + 6 = b
7 = b
b = 7
Now, our y-intercept (b) is 7.
We can now find the slope-intercept form
y = mx + b
y = -3x + 7 is our slope-intercept form
And the standard form of the linear function is
Ax + By = C where A, B, & C are real numbers
3x + y = 7 is the standard form
We will first find the slope by using m = (y2 - y1) / (x2 - x1) where (x1,y1) &
(x2, y2) are the two given points which are (2,1) & (3,-2).
Let's solve now
m = (y2 - y1) / (x2 - x1)
m = (-2 - 1) / (3 - 2)
m = -3 / 1
m = -3
Now, our slope is m = -3
Next, we will find the y-intercept (b) by using the slope m=-3 and one of the two points like (2,1)
y = mx + b
1 = -3(2) + b
1 = -6 + b
1 + 6 = b
7 = b
b = 7
Now, our y-intercept (b) is 7.
We can now find the slope-intercept form
y = mx + b
y = -3x + 7 is our slope-intercept form
And the standard form of the linear function is
Ax + By = C where A, B, & C are real numbers
3x + y = 7 is the standard form
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