Answer:
7. 4/3
8. 5/5[tex]\sqrt5[/tex]
9. 1
10. 3/2[tex]\sqrt3\\[/tex]
11. [tex]\sqrt2[/tex]
12. [tex]\sqrt5[/tex]/5
explanation:
# Fisrt you need to identify what is the given angle then find the Hypotenuse,Adjacent and Opposite side
#2 Use the SOH-CAH-TOA to solve the missing sides of a right triangle
SOH (sin=Opposite/Hypotenuse
CAH (cosine=Adjacent/Hypotenuse)
TOA ( tangent=Opposite/Adjacent)
Step-by-Step solving:
8. [tex]\frac{\sqrt{5} }{5}[/tex] x[tex]\sqrt{5}[/tex]/[tex]\sqrt{5[/tex] = 5/5[tex]\sqrt{5[/tex]
10. [tex]\sqrt{3[/tex]/2 x [tex]\sqrt{3[/tex]/[tex]\sqrt3[/tex] = 3/2[tex]\sqrt{3[/tex]
12. 1/[tex]\sqrt{5[/tex] x [tex]\sqrt{5[/tex]/[tex]\sqrt{5[/tex] = [tex]\sqrt{5[/tex]/5
Hope it helps:)
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