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Use a variable to represent the unknown quantity then write an equationfrom the given information. Explain how you arrived at your answer.

1.
The area of a garden is 160 m2. Suppose the length of the garden is 3 m morethan twice its width. What is the length of the garden?

2.
The length of a tarpaulin is 3 ft. more than thrice its width and its area is 126 ft.².What is the length of the tarpaulin?

3.
Mario and Kenneth work in a car wash station. The time that Mario takes inwashing a car alone is 20 minutes less than the time that Kenneth takes inwashing the same car. If both of them work together in washing the car, it willtake them 90 minutes. How long will it take each of them to wash the car?

Sagot :

length is 3
and let x the width
the equation will be 3x=160
160/3=53.1
AnneC
1) Let    x=width   ;   2x+3=length
   Given: A=160m²

[tex]A = x(2x+3)[/tex]

[tex]160 = x(2x+3) 160 = 2x^2+3x 0 = 2x^2+3x -160 [/tex]

Using the quadratic formula you will get [tex]x = \frac{-3+\sqrt{1289} }{4} [/tex]
Therefore, length=[tex]\boxed{ \frac{3+ \sqrt{1289} }{2}m}[/tex]


2) Let x=width   ;   3x+3=length
   Given: A=126 ft²

[tex]A=x(3x+3)[/tex]

[tex]126 = x(3x+3) 126 = 3x^2 + 3x 42 = x^2 +x 0 = x^2 +x -42 0 = (x+7)(x-6) x = -7 ; x = 6[/tex]

Use x=6  ;  Therefore, [tex]\boxed{length=21 ft}[/tex]


3) Rate of Kenneth = [tex] \frac{1}{x} [/tex]
    Rate of Mario = [tex] \frac{1}{x-20} [/tex]

[tex] \frac{90}{x} + \frac{90}{x-20} =1[/tex]

[tex] \frac{90x-1800+90x}{x(x-20)}=1 [/tex]