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Solving Rational Algebraic Equations Transformable to Quadratic Equation

1) x+[tex] \frac{8}{x-2} [/tex]=1+[tex] \frac{4x}{x-2} [/tex]


2) [tex] \frac{2x ^{2} }{5} [/tex]+[tex] \frac{5x}{4} [/tex]=10


Sagot :

Answer:

The transformed quadratic equations are:

1. [tex]x^2-7x+10=0[/tex]

2. [tex]8x^2+25x-200=0[/tex]

Step-by-step explanation:

Our aim here is to transform the given rational equations to quadratic equations.

For the given rational equations

1.  [tex]x+\frac{8}{x-2} =1+\frac{4x}{x-2}[/tex]

2. [tex]\frac{2x^2}{5} +\frac{5x}{4} =10[/tex]

Transforming the given rational equations to quadratic equations

1. For the first rational equation, get the LCD of both sides of the equation

  [tex]x+\frac{8}{x-2} =1+\frac{4x}{x-2}[/tex]

  [tex]\frac{x(x-2)+8}{x-2} =\frac{x-2+4x}{x-2}[/tex]

  Multiply both side of the equation by x - 2 and simplify their numerators

  [tex]x^2-2x+8=5x-2[/tex]

 Transpose 5x and - 2 to the left side of the equation, combine like  

  terms and simplify

  [tex]x^2-5x-2x+8+2=0[/tex]

  [tex]x^2-7x+10=0[/tex]

2. The second rational equation is more simple, so we proceed to getting the LCD and use the same steps like the first example.

   [tex]\frac{2x^2}{5} +\frac{5x}{4} =10[/tex]

  [tex]\frac{4(2x^2)+5(5x)}{20} =10[/tex]

 Cross-multiply and simplify the equation

  [tex]8x^2+25x=200[/tex]

  [tex]8x^2+25x-200=0[/tex]

Therefore, the transformed quadratic equations are  [tex]x^2-7x+10=0[/tex]  and

[tex]8x^2+25x-200=0[/tex]

To learn more about quadratic equations, just click on the following links:

* Definition of quadratic equation

  https://brainly.ph/question/202117

* Solving quadratic equations

  https://brainly.ph/question/1687510

* Examples of Non-quadratic equations

  https://brainly.ph/question/804674

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