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Sagot :
C = number of caviar
B = number bologna
L = number of liverwurst
1st equation
C + B + L = 100
2nd equation 10 cent = $1/10
5C + 2B + L/10 = 100
by elimination,
first divide the 2nd equation by 10 and subtract to 1st equation so that we can eliminate L
then we can get
49C + 19B = 900 ,simplifying divide the equation by 10 to becomes more realistic to the problem
4.9 C + 1.9 B = $90 (equation 3)
to make exactly dollar by selling caviar & bologna she'll need to sell some multiple of 10 sandwiches
C + B = 10 n
the possible values of n must be multiple of 3 so lets try n = 3,6,9 and so on
by solving further
For n=3, B = 19
For n=6, B = 68
For n=9, B = 117 which is impossible
If B = 19, then C = 11 and L = 70.
If B = 68, then C = -8 which is impossible
The only possible answer
11 caviar
19 bologna
70 Liverwurst
B = number bologna
L = number of liverwurst
1st equation
C + B + L = 100
2nd equation 10 cent = $1/10
5C + 2B + L/10 = 100
by elimination,
first divide the 2nd equation by 10 and subtract to 1st equation so that we can eliminate L
then we can get
49C + 19B = 900 ,simplifying divide the equation by 10 to becomes more realistic to the problem
4.9 C + 1.9 B = $90 (equation 3)
to make exactly dollar by selling caviar & bologna she'll need to sell some multiple of 10 sandwiches
C + B = 10 n
the possible values of n must be multiple of 3 so lets try n = 3,6,9 and so on
by solving further
For n=3, B = 19
For n=6, B = 68
For n=9, B = 117 which is impossible
If B = 19, then C = 11 and L = 70.
If B = 68, then C = -8 which is impossible
The only possible answer
11 caviar
19 bologna
70 Liverwurst
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