you may change the two given hours into an improper fraction or you can have it in mixed..
Let's have it done first in mixed number
[tex]2 \frac{1}{3} + 2 \frac{1}{2} [/tex]
since this is addition, you may first add the two whole numbers
having it as
[tex]2\frac{1}{3} [/tex]
+ [tex]2 \frac{1}{2} [/tex]
[tex]4 and \frac{1}{3} + \frac{1}{2} [/tex]
for the fractions 1/3 and 1/2, find first the LCD which in this case is 6
[tex] \frac{1}{3} + \frac{1}{2} = \frac{1(2) +1(3)}{6} [/tex]
= [tex] \frac{5}{6} [/tex]
therefore your answer will be [tex]4 \frac{5}{6} [/tex]
If we do it by changing it into improper fraction, we'll have it as:
[tex]2 \frac{1}{3} = \frac{7}{3} [/tex]
[tex]2 \frac{1}{2} = \frac{5}{2} [/tex]
still find the LCD
[tex] \frac{7}{3} + \frac{5}{2} = \frac{7(2) +5(3)}{6} [/tex]
[tex]= \frac{14 + 15}{6} [/tex]
Converting it into a mixed number you'll have:
[tex]4 \frac{5}{6} [/tex]
