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Sagot :
1.) Three consecutive odd integers
Let 'x' be the first number
'x+2' be the second number
'x+4' be the third number
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-Three times the largest is seven times the smallest
7x = 3(x+4)
-----------------------------------
Distribute 3 to the quantity (x+4)
7x = 3x + 12
-----------------------------------
Transpose 3x to the left side of the equation
7x - 3x = 12
-----------------------------------
Combine like terms
4x = 12
----------------------------------
Divide the whole equation with 4
x = 3
---------------------------------
x = 3
x + 2 = 3 + 2
x + 2 = 5
x + 4 = 3 + 4
x + 4 = 7
---------------------------------
Therefore the three consecutive odd integers are 3, 5, 7.
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2.) Two numbers are consecutive even
Let 'x' be the first number
'x+2' be the second number
-----------------------------------------------------
-If twice the smaller is 18 more than the larger
2x = (x+2) + 18
---------------------------------
Remove parenthesis
2x = x + 2 + 18
--------------------------------
Transpose x to the left side of the equation
2x - x = 2 + 18
-------------------------------
Combine like terms
x = 20
-------------------------------
x = 20
x + 2 = 20 + 2
x + 2 = 22
------------------------------
Therefore the two consecutive even numbers are 20, 22.
Let 'x' be the first number
'x+2' be the second number
'x+4' be the third number
---------------------------------------------
-Three times the largest is seven times the smallest
7x = 3(x+4)
-----------------------------------
Distribute 3 to the quantity (x+4)
7x = 3x + 12
-----------------------------------
Transpose 3x to the left side of the equation
7x - 3x = 12
-----------------------------------
Combine like terms
4x = 12
----------------------------------
Divide the whole equation with 4
x = 3
---------------------------------
x = 3
x + 2 = 3 + 2
x + 2 = 5
x + 4 = 3 + 4
x + 4 = 7
---------------------------------
Therefore the three consecutive odd integers are 3, 5, 7.
---------------------------------------------------------------------------------------
2.) Two numbers are consecutive even
Let 'x' be the first number
'x+2' be the second number
-----------------------------------------------------
-If twice the smaller is 18 more than the larger
2x = (x+2) + 18
---------------------------------
Remove parenthesis
2x = x + 2 + 18
--------------------------------
Transpose x to the left side of the equation
2x - x = 2 + 18
-------------------------------
Combine like terms
x = 20
-------------------------------
x = 20
x + 2 = 20 + 2
x + 2 = 22
------------------------------
Therefore the two consecutive even numbers are 20, 22.
1. The integers be x(smallest), x + 2 and x + 4(largest) since they are consecutive odd integers
3 times the largest is 7 times the smallest.
3(x + 4) = 7x
Multiply
3x + 12 = 7x
Transpose 6 and 7x
3x - 7x = -12
Subtract
-4x = -12
Divide by -4 both sides
-4x/-4 = -12/-4
Therefore
x = 3 (first odd integer)
Let's now substitute the value of x to determine the other two odd integers
second odd integer
3 + 2 = 5
third odd integer
3 + 4 = 7
Therefore the odd integers are 3, 5 and 7
2. Let the consecutive even be x and x + 2(largest)
Twice the smallest is 18 more than the larger
2x = (x + 2) + 18
Add 2 to 18
2x = x + 20
Transpose x
2x - x = 20
Therefore
x = 20
Let's now substitute the value of x to determine the value of the largest even
x + 2
20 + 2
Therefore
22 is the largest even and 20 is the smallest
I hope it helps
3 times the largest is 7 times the smallest.
3(x + 4) = 7x
Multiply
3x + 12 = 7x
Transpose 6 and 7x
3x - 7x = -12
Subtract
-4x = -12
Divide by -4 both sides
-4x/-4 = -12/-4
Therefore
x = 3 (first odd integer)
Let's now substitute the value of x to determine the other two odd integers
second odd integer
3 + 2 = 5
third odd integer
3 + 4 = 7
Therefore the odd integers are 3, 5 and 7
2. Let the consecutive even be x and x + 2(largest)
Twice the smallest is 18 more than the larger
2x = (x + 2) + 18
Add 2 to 18
2x = x + 20
Transpose x
2x - x = 20
Therefore
x = 20
Let's now substitute the value of x to determine the value of the largest even
x + 2
20 + 2
Therefore
22 is the largest even and 20 is the smallest
I hope it helps
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