Answer:
1.)? i don't know sorry
2.)
Answer:
[tex](3y - 5) {}^{2} • (4y + 7)[/tex]
Solution:
Factoring 12y²+y-35
The first term is, 12y² its coefficient is 12 .
The middle term is, +y its coefficient is 1 .
The last term, "the constant", is -35
Step-1 : Multiply the coefficient of the first term by the constant 12 • -35 = -420
Step-2 : Find two factors of -420 whose sum equals the coefficient of the middle term,
which is 1.
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -20 and 21
12y² - 20y + 21y - 35
Step-4 : Add up the first 2 terms, pulling out like factors :
4y • (3y-5)
Add up the last 2 terms, pulling out common factors :
7 • (3y-5)
Step-5 : Add up the four terms of step 4 :
(4y+7) • (3y-5)
Which is the desired factorization
Multiply (3y-5) by (3y-5)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (3y-5) and the exponents are :
1 , as (3y-5) is the same number as (3y-5)¹
and 1 , as (3y-5) is the same number as (3y-5)¹
The product is therefore, (3y-5)^(1+1) = (3y-5)²
#sorry ha number 2 lng po alam ko
#CarryOnLearning
