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a 7500 kg truck travelling away at 5.0 m/s east collides with a 1500 kg car moving at 20.0 m m/s. after collision the two vehicles remain tangled together.with what speed and what direction does the wreckage begin to move?

Sagot :

indrawboy

The speed of the two vehicles is 7.5 m/s to the east

Further explanation

Momentum is the product of the mass of an object and its velocity

[tex]\large{\boxed{\bold{P=m\times v}}[/tex]

If 2 objects with mass A and mass B collide with velocity va and vb, then the law of conservation of momentum will occur:

mava + mbvb = mava '+ mbvb'

can be stated:

the total momentum before the collision is equal to the total momentum after the collision (in the absence of external forces)

Collisions between these 2 objects can be

elastic, inelastic, and completely inelastic (the colliding objects stick together)

In elastic collisions, the coefficient of restitution (e) = 1., inelastic: 0 <e <1, completely inelastic: e = 0

Completely inelastic occurs when after the collision process makes both objects stick and move at the same speed

v1 '= v2' = v '

m1v1 + m2v2 = (m1 + m2) v '

a 7500 kg truck traveling away at 5.0 m / s east collides with a 1500 kg car moving at 20.0 m m / s. after collision the two vehicles remain tangled together

Then this event can be put into completely inelastic

Assuming the direction of the truck and the car are the same, towards the east, the speed of both is positive

m1v1 + m2v2 = (m1 + m2) v '

7500.5 + 1500.20 = (7500 + 1500) v '

v' = 7.5 m/s with the speed direction to the east (positive = east)

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