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B. Solve the percentage composition of all atoms in a compound
1. AICI3
2. K20
3. NaBr
4. Zn(OH)2
5. Ag3PO4​

B Solve The Percentage Composition Of All Atoms In A Compound1 AICI32 K203 NaBr4 ZnOH25 Ag3PO4 class=

Sagot :

Solution (1)

Step 1: Calculate the molar mass of AlCl₃.

molar mass = (26.98 g/mol × 1) + (35.45 g/mol × 3)

molar mass = 133.33 g/mol

Step 2: Calculate the percentage composition of AlCl₃.

For mass percent of Al

[tex]\text{mass percent of Al} = \frac{\text{26.98 g/mol × 1}}{\text{133.33 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Al = 20.24\%}}[/tex]

For mass percent of Cl

[tex]\text{mass percent of Cl} = \frac{\text{35.45 g/mol × 3}}{\text{133.33 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Cl = 79.76\%}}[/tex]

Solution (2)

Step 1: Calculate the molar mass of K₂O.

molar mass = (39.10 g/mol × 2) + (16.00 g/mol × 1)

molar mass = 94.20 g/mol

Step 2: Calculate the percentage composition of K₂O.

For mass percent of K

[tex]\text{mass percent of K} = \frac{\text{39.10 g/mol × 2}}{\text{94.20 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of K = 83.01\%}}[/tex]

For mass percent of O

[tex]\text{mass percent of O} = \frac{\text{16.00 g/mol × 1}}{\text{94.20 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of O = 16.99\%}}[/tex]

Solution (3)

Step 1: Calculate the molar mass of NaBr.

molar mass = (22.99 g/mol × 1) + (79.90 g/mol × 1)

molar mass = 102.89 g/mol

Step 2: Calculate the percentage composition of NaBr.

For mass percent of Na

[tex]\text{mass percent of Na} = \frac{\text{22.99 g/mol × 1}}{\text{102.89 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Na = 22.34\%}}[/tex]

For mass percent of Br

[tex]\text{mass percent of Br} = \frac{\text{79.90 g/mol × 1}}{\text{102.89 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Br = 77.66\%}}[/tex]

Solution (4)

Step 1: Calculate the molar mass of Zn(OH)₂.

molar mass = (65.39 g/mol × 1) + (16.00 g/mol × 2) + (1.008 g/mol × 2)

molar mass = 99.41 g/mol

Step 2: Calculate the percentage composition of Zn(OH)₂.

For mass percent of Zn

[tex]\text{mass percent of Zn} = \frac{\text{65.39 g/mol × 1}}{\text{99.41 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Zn = 65.78\%}}[/tex]

For mass percent of O

[tex]\text{mass percent of O} = \frac{\text{16.00 g/mol × 2}}{\text{99.41 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of O = 32.19\%}}[/tex]

For mass percent of H

[tex]\text{mass percent of H} = \frac{\text{1.008 g/mol × 2}}{\text{99.41 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of H = 2.03\%}}[/tex]

Solution (5)

Step 1: Calculate the molar mass of Ag₃PO₄.

molar mass = (107.9 g/mol × 3) + (30.97 g/mol × 1) + (16.00 g/mol × 4)

molar mass = 418.7 g/mol

Step 2: Calculate the percentage composition of Ag₃PO₄.

For mass percent of Ag

[tex]\text{mass percent of Ag} = \frac{\text{107.9 g/mol × 3}}{\text{418.7 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Ag = 77.31\%}}[/tex]

For mass percent of P

[tex]\text{mass percent of P} = \frac{\text{30.97 g/mol × 1}}{\text{418.7 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of P = 7.40\%}}[/tex]

For mass percent of O

[tex]\text{mass percent of O} = \frac{\text{16.00 g/mol × 4}}{\text{418.7 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of O = 15.29\%}}[/tex]

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