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the distance april walk from home to school is 120 m and 80 m when she goes to church from home may estimates that the distance april walk when she goes directly to church coming from school is 180 m dunes estimation is 210 l which estimation is feasible justify your answer​

The Distance April Walk From Home To School Is 120 M And 80 M When She Goes To Church From Home May Estimates That The Distance April Walk When She Goes Directl class=

Sagot :

Johnjihn7573

Answer:

Answer:

Xylie's estimation is more feasible than Realee's estimation.

Step-by-step explanation:

If we assume that Klark's school is at the northern part of his house and the church is at the eastern part of his house, the path that can be made is a right triangle. To fully understand what I'm saying, I provided an image that contains the drawing of the problem.

Now looking at the drawing, the missing side of the right triangle represents the distance from school to church.

To know which estimation is feasible or the best, we must solve the missing side or the hypotenuse then we will compare it to the given estimations made by Xylie and Realee in the problem.

Solving for the hypotenuse:

h^2h

2

= a^2 + b^2a

2

+b

2

where a = 120 m and b = 80 m

h = \sqrt{(120^2) + (80^2)}

(120

2

)+(80

2

)

h = 144.2221 m

Now we compare the answer we obtained from the estimations. The estimations of the distance from school to church is 180 m and 210 m. Obviously the nearest number to 144.2221 is 180, hence, 180 meters, the distance estimated by Xylie is the feasible estimation.

Practice more right triangle problems here! https://brainly.ph/question/103151

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