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EVALUATION INSTRUCTION: Solve the following word problems using the kinetic and potential energy formulas. Show the solution at the box

Formula: OR KE=0.5 m2
v = velocity or speed
g = 10 m/s/s

or

PE= m•g•h
m = mass in kg
h = height in meters

1. You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has energy. Calculate it.

2. A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 1.5 kg. The carriage has energy. Calculate it.

3. A car is traveling with a velocity of 40 m/s and has a mass of 1120 kg. The car has energy. Calculate

4. A cinder block is sitting on a platform 20 m high. It weighs 7.9 kg. The block has energy. Calculate

5. A roller coaster is at the top of a 72 m hill and weighs 134 kg. The coaster (at this moment) has energy. Calculate it.

6. There is a bell at the top of a tower that is 45 m high. The bell weighs 19 kg. The bell has energy Calculate it.

7. Determine the kinetic energy of a 1000-kg roller coaster car that is moving with a speed of 20.0 m/s.

8. If the roller coaster car in the above problem were moving with twice the speed, then what would be its new kinetic energy?

9. A cart is loaded with a brick and pulled at constant speed along an inclined plane to the height of a seat-top. If the imass of the loaded cart is 3.0 kg and the height of the seat top is 0.45 meters, then what is the potential energy of the loaded cart at the height of the seat top?​

Sagot :

OkumuraKoshuu

Answer:

1. PE = (2.1)(30)

= 63

2. PE = (1.5)(21)

= 31.5

3. KE = 1/2 (1120)(40)²

= 896000

4. PE = (7.9)(20)

= 158

5. KE = 1/2 (134)(72)²

= 347328

6. KE = 1/2 (19)(45)²

= 19237.5

7. KE = 1/2 (1000)(20.0)²

= 200000

8. KE = 1/2 (134) (72(2))²

= 1389312

9. PE= (3.0)(0.45)

= 1.35

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