lj10jauregui
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SPEED PROBLEMS

1. A car travels along a road at a steady speed of 60 mph. How far will it travel in 6 hours?

2. A train covers a distance of 480 mi in 8 hours. If it travels at a constant speed, how fast is it traveling?

3. John walks at a steady speed of 3 mph. How long will it take him to travel 24 miles?

4. A car travel at a constant speed of 65 mph. How far will it have traveled in 4 hours?

5. Melanie completes a long distance run at an average speed of 6 mph. If it takes her 3 hours, how fas did she run?

6. Sarah cycles 30 mi to her grandmother's house at a steady speed of 10 mph. If she leave home at 2:00 pm, what time will she arrive?

Sagot :

indrawboy

Speed (velocity) depends on distance and time travel

Further explanation  

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration  

At constant velocity motion:  

the speed of vo = v = constant  

acceleration = a = 0  

Δx = vt or x = xo + vt  

An equation of constant velocity motion  

[tex]\rm D=v\times t[/tex]

D =distance , m

v = velocity, m/s

t = time, s

1. speed = v= 60 mph, t = 6 hours

[tex]\rm D=60\times 6=\boxed{\bold{360~miles}}[/tex]

2. distance = d =480 miles, t = 8 hours

[tex]\rm v=\dfrac{480}{8}=\boxed{\bold{6~mph}}[/tex]

3. speed = v = 3 mph, d = 24 miles

[tex]\rm t=\dfrac{24}{3}=\boxed{\bold{8~hours}}[/tex]

4. speed = v = 65 mph, t = 4 hours

[tex]\rm d=65\times 4=\boxed{\bold{260~miles}}[/tex]

5. speed = v = 6 mph, t = 4 hours

[tex]\rm d=6\times 3 =\boxed{\bold{18~miles}}[/tex]

6. d = 30 miles, v = 10 mph, initial time = 2:00 pm

[tex]\rm t=\dfrac{30}{10}=3~hours[/tex]

time arrive :

[tex]\rm 2:00~pm+3~hours=\boxed{\bold{5:00~pm}}[/tex]

Learn more  

uniformly accelerated motion  

https://brainly.ph/question/2132892  

https://brainly.ph/question/2088325  

the probe’s velocity relative to the earth  

https://brainly.ph/question/1467317  

Uniformly accelerated motion: vertical dimension  

https://brainly.ph/question/2098492

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