TheOnlyPro
Answered

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3. Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:

(a) broke even
(b) lost 4 cents
(c) gained 4 cents
(d) lost 10 cents
(e) gained 10 cent

with solution po plsss

Sagot :

CosetteWeinberg

✏️Answer✏️

    (d) lost 10 cents

Step-by-step explanation:

Selling price of the first pipe = $1.20

Profit = 20%

Let’s try to find the cost price of the first pipe

CP = Selling price - Profit

CP = 1.20 - 20% of CP

CP = 1.20 - 0.20CP

CP + 0.20CP = 1.20

1.20CP = 1.20

CP = 1.201.20

CP = $ 1

Selling price of the Second pipe = $1.20

Loss = 20%

Let’s try to find the cost price of the second pipe

CP = Selling price + Loss

CP = 1.20 + 20% of CP

CP = 1.20 + 0.20CP

CP - 0.20CP = 1.20

0.80CP = 1.20

CP = 1.200.80

CP = $1.50

Therefore, total cost price of the two pipes = $1.00 + $1.50 = $2.50

And total selling price of the two pipes = $1.20 + $1.20 = $2.40

Lose = $2.50 – $2.40 = $0.10

Therefore, Mr. Jones loss 10 cents.

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#CarryOnLearning

Vicola8957

3. Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:

(a) broke even

(b) lost 4 cents

(c) gained 4 cents

(d) lost 10 cents

(e) gained 10 cent

hope it helps

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