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Sagot :
[tex]\underline{\underline{\large{\green{\cal{GIVEN:}}}}}[/tex]
The angle with respect to the horizontal as baseball returns to the ground is θ = 45°.
[tex]\underline{\underline{\large{\green{\cal{REQUIRED:}}}}}[/tex]
What is the acceleration of a baseball thrown into the air at an angle of 45°.
[tex]\underline{\underline{\large{\green{\cal{EXPLANATION:}}}}}[/tex]
Hi! Brainly User, to answer the question, we need to remember few concepts first:
In projectile motion for any baseball once it is thrown and is in the air, gravity is the only force affecting it after ignoring the force of air resistance. Gravity conspires to produce constant acceleration on the baseball in the downward direction, regardless of where it is in the trajectory.
This type of acceleration is described as constant, and it is also referred to as acceleration due to gravity, or g, and has a value of [tex]\rm{9.8 m/s^2}[/tex]. It is always acting downwards towards the center of the earth.
Option A: This is wrong because velocity is represented by 0 m/s. ✘
Option B: This is wrong because it gives the value of gravitational acceleration without including appropriate units. ✘
Option C: This is incorrect, as it suggested no acceleration but almost constant activity from gravity in relation to the baseball. ✘
Option D: The answer to this question is: This is the correct answer. The negativity of the value means that the orientation of the acceleration is this way, downwards. ✓
Final Answer:
[tex]\therefore[/tex] The acceleration of a baseball thrown into the air at an angle of 45° is D. -9.8 m/s².
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