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I go to the store with x money. I spent half of my money and P10 more. I had exactly P30 left. How much money did I have at first?​

Sagot :

NoahBadilla

PROBLEM SOLVING

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[tex]\rm{\underline{QUESTION:}}[/tex]

You go to the store with x money. I spent half of my money and P10 more. I had exactly P30 left. How much money did I have at first?​

[tex]\\[/tex]

[tex]\rm{\underline{SOLUTION:}}[/tex]

Let x be the unknown amount of money. Based on your given problem,

  • You spent half of your money. This can be expressed as [tex]\frac{x}{2}[/tex], where x is the unkown number divided by 2.
  • You spent P10 more and had exactly P30 left.

[tex]\\[/tex]

So our equation will be:

  • [tex]x - (\frac{x}{2} + 10) = 30[/tex]

Solving for x:

  • [tex]x - (\frac{x}{2} + 10) = 30[/tex]
  • [tex]x - \frac{x}{2} - 10 = 30[/tex]
  • [tex]\frac{2x}{2} - \frac{x}{2} - 10 = 30[/tex]
  • [tex]\frac{x}{2} - 10 = 30[/tex]
  • [tex]{\frac{x}{2} - 10 + 10 = 30+10}[/tex]
  • [tex]\frac{x}{2} =40[/tex]

Lastly, multiply both sides by 2 to find x. The other half of your spent money will be found by multiplying.

  • [tex]{\frac{x}{2} \times 2=40 \times 2}[/tex]
  • [tex]x = \green{80}[/tex]

[tex]\\[/tex]

Hence, you had P80 before going to the store.

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[tex]\large{\boxed{\tt{\blue{06/17/2024}}}}[/tex]

fIorcabriIIos25

Answer:

70

Step-by-step explanation:

30 left

10 more spent

30x2+10

60+10

= 70

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