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As the angle of incidence is increased for a ray incident on a reflecting surface, the angle
between the incident and reflected rays ultimately approaches what value?

Sagot :

ashrieIIe

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[tex]\pink{\mathbb{\huge{꧁ᬊᬁ~ANSWER~ᬊ᭄꧂}}}[/tex]

[tex]\pink{\boxed{\sf\pink{໒꒰ྀིᵔ ᵕ ᵔ ꒱ྀི১}}}[/tex] As the angle of incidence is increased for a ray incident on a reflecting surface, the angle between the incident and reflected rays ultimately approaches [tex]\blue{\underline{\sf\pink{180°}}}[/tex].

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[tex]\large\sf\pink{-ˏˋ ~REASONING~ ˊˎ}[/tex]

[tex]\sf\pink{ᯓ★}[/tex] The law of reflection states that the angle of incidence (θi) is equal to the angle of reflection (θr).

  • Mathematically, θi = θr.

[tex]\sf\pink{ᯓ★}[/tex] As the angle of incidence increases, the angle of reflection also increases by the same amount, as per the law of reflection.

[tex]\sf\pink{ᯓ★}[/tex] When the angle of incidence reaches 90° (perpendicular to the surface), the angle of reflection also becomes 90°.

[tex]\sf\pink{ᯓ★}[/tex] At this point, the angle between the incident ray and the reflected ray is 180°, as they are traveling in opposite directions.

[tex]\sf\pink{ᯓ★}[/tex] This is the maximum possible angle between the incident and reflected rays, as per the law of reflection.

[tex]\bold{\small\pink{⋆˚࿔~ ashrieIIe~˚⋆}}[/tex] [tex]\pink{\heartsuit}[/tex]

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