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Sagot :
a. Let
x and x+9 so... à x+x+9=25 à
2x+9=25 à 2x=25-9 à
2x/2=16/2 à x=8
b. Let x be one of the number and x+5 for the other since it’s a multiple of 5 so... x+x+5=55 à 2x/2=55/2 à x=27.5 since it’s a consecutive multiple the two numbers are 27 and 28.
c. 3/5th of a number is 4 more than 1/2 the number the equation is à 3/5x = 4+1/2x à 10[3/5x = 4+1/2x] à 6x = 40+5x à 6x-5x = 40 à x = 40
d. When 142 is added to a number, the result is 64 more than 3 times the number the equation is à 142+x = 64+3x à 142-64 = 3x-x à 2x/2 = 78/2 à x = 9
e. We assume that the three consecutive numbers are x, x+1 and x+2 so... x+x+1+x+2 = 243 à 3x+3 = 243 à 3x = 243-3 à 3x/3 = 240/3 à x = 80, x+1 à 80+1 à81 and x+2 à 80+2 à 82 so the numbers are 80, 81 and 82
f. Let x be the numerator so... = à 2[(x+3)-1] [ = à 2x+14 = 3x+9-3 à2x+14 = 3x+6 à 3x-2x = 14-6 à x = 8
g. Trial and Error 52 and 25 are the answers.
h. Let the one’s be 2x+1 and the ten’s be x so... x+2x+1 = 7 à 3x+1 = 7 à 3x = 7-1 à 3x/3 = 6/3 à x = 2 so the tens is 2 and the ones is 2x+1 à 2(2)+1 à 5 so the digit is 25
i. We assume that the three consecutive numbers are x, x+4 and x+8 so... x+x+4+x+8 = 444 à 3x+12 = 444 à 3x = 144-12 à3x/3 = 132/3 àx = 44, x+4 à 44+4 à48 and x+8 à 44+8 à 52 so the numbers are 44, 48 and 52
b. Let x be one of the number and x+5 for the other since it’s a multiple of 5 so... x+x+5=55 à 2x/2=55/2 à x=27.5 since it’s a consecutive multiple the two numbers are 27 and 28.
c. 3/5th of a number is 4 more than 1/2 the number the equation is à 3/5x = 4+1/2x à 10[3/5x = 4+1/2x] à 6x = 40+5x à 6x-5x = 40 à x = 40
d. When 142 is added to a number, the result is 64 more than 3 times the number the equation is à 142+x = 64+3x à 142-64 = 3x-x à 2x/2 = 78/2 à x = 9
e. We assume that the three consecutive numbers are x, x+1 and x+2 so... x+x+1+x+2 = 243 à 3x+3 = 243 à 3x = 243-3 à 3x/3 = 240/3 à x = 80, x+1 à 80+1 à81 and x+2 à 80+2 à 82 so the numbers are 80, 81 and 82
f. Let x be the numerator so... = à 2[(x+3)-1] [ = à 2x+14 = 3x+9-3 à2x+14 = 3x+6 à 3x-2x = 14-6 à x = 8
g. Trial and Error 52 and 25 are the answers.
h. Let the one’s be 2x+1 and the ten’s be x so... x+2x+1 = 7 à 3x+1 = 7 à 3x = 7-1 à 3x/3 = 6/3 à x = 2 so the tens is 2 and the ones is 2x+1 à 2(2)+1 à 5 so the digit is 25
i. We assume that the three consecutive numbers are x, x+4 and x+8 so... x+x+4+x+8 = 444 à 3x+12 = 444 à 3x = 144-12 à3x/3 = 132/3 àx = 44, x+4 à 44+4 à48 and x+8 à 44+8 à 52 so the numbers are 44, 48 and 52
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