Answer:
The distance of the car traveled is 375 m.
Explanation:
Formula to be use for Motions Along a Straight Line
[tex]v=v_{0} +at[/tex] equation 1
[tex]x=v_{0} t + \frac{1}{2} at^2[/tex] equation 2
where
[tex]v[/tex] is the final velocity, unit is in m/s
[tex]v_{0}[/tex] is the initial velocity, unit is in m/s
[tex]x[/tex] is the distance, unit is in meters (m)
[tex]a[/tex] is the acceleration, unit is in m/[tex]s^2[/tex]
[tex]t[/tex] is the time duration of motion, unit is in seconds (s)
For the given information
[tex]v_{0}=0[/tex] because the car starts from rest
[tex]v=50m/s[/tex]
[tex]t=15s[/tex]
Solving the problem
1. Using equation 1, solve for the acceleration
[tex]v=v_{0} +at[/tex]
50 m/s = 0 + a (15 s)
Divide both sides of the equation by 15 s, we get:
a = [tex]\frac{50 m/s}{15s}[/tex]
a = 3.33 m/[tex]s^2[/tex]
2. Using equation 2, substitute the value of the acceleration then solve for x
[tex]x=v_{0} t + \frac{1}{2} at^2[/tex]
[tex]x =0+\frac{1}{2} (3.33m/s^2)(15s)^2[/tex]
x = 375 m
Therefore, the distance the car has traveled is 375 m within 15 seconds.
To learn more about this topic, just click on the following links:
- Definition of acceleration
https://brainly.ph/question/2048479
https://brainly.ph/question/104912
https://brainly.ph/question/503065
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