Answer:
In a plane mirror we know that, image distance is equal to the object distance. Consider a right angled triangle whose base is 4m with the mirror in the middle [in agreement to the condition given]. The height of the right angled triangle would be 1.4m with the mirror's height h.
Now applying the concept of similarity of triangles
24=h1.4" role="presentation" style="margin: 0px; padding: 0px; display: inline-table; font-style: normal; font-weight: normal; line-height: normal; font-size: 15px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; position: relative;">24=h1.424=h1.4
On simplification, h=0.7m
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Other Answers
Shivam Raj, studied at Naman Vidya, Masipirhi
Answered 3 years ago
The minimum height required to view the full image of an object is half the height of the plane mirror.
So according to this question , the height is given 1.4m, so the minimum height of required mirror will be 0.7m.
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